Question

question 5
1 pts
if a man and woman both have type ab blood, what is the likelihood that their only child will have type ab blood?
75%
50%
100%
25%
0%

Explanation:

Step1: Determine the genotypes of parents

Blood type AB has the genotype \(I^A I^B\). So both parents have genotype \(I^A I^B\).

Step2: Create a Punnett square

The possible gametes from each parent are \(I^A\) and \(I^B\). The Punnett square is:

	\(I^A\)	\(I^B\)
\(I^B\)	\(I^A I^B\) (Type AB)	\(I^B I^B\) (Type B)

Step3: Calculate the probability of Type AB

There are 4 possible genotypes. The number of \(I^A I^B\) (Type AB) genotypes is 2. The probability is \(\frac{2}{4}=\frac{1}{2} = 50\%\)

Answer:

50%