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Question
question 30 (3 points)
the table below gives the number of worldwide internet users, in millions, for the years between 1995 and 2007.
| year | users (millions) | year | users (millions) |
|---|---|---|---|
| 1996 | 36 | 2003 | 719 |
| 1997 | 70 | 2004 | 817 |
| 1998 | 147 | 2005 | 1018 |
| 1999 | 248 | 2006 | 1093 |
| 2000 | 361 | 2007 | 1215 |
| 2001 | 536 |
the cubic function that is the best fit for the data, with ( y ) equal to the number of millions of users and ( x ) equal to the number of years from 1990 is given by ( y = -0.613x^3 + 23.835x^2 - 179.586x + 385.670 ). use the model to predict the number of users in 2010.
- 1360 million
- 1424 million
- 1030 million
- 1215 million
Step1: Determine x for 2010
x is years from 1990. 2010 - 1990 = 20, so x = 20.
Step2: Substitute x=20 into the cubic function
The function is \( y = -0.613x^3 + 23.835x^2 - 179.586x + 385.670 \).
Substitute x = 20:
\( y = -0.613(20)^3 + 23.835(20)^2 - 179.586(20) + 385.670 \)
Calculate each term:
- \( -0.613(8000) = -4904 \)
- \( 23.835(400) = 9534 \)
- \( -179.586(20) = -3591.72 \)
- Constant term: 385.670
Now sum them: \( -4904 + 9534 - 3591.72 + 385.670 \)
First, -4904 + 9534 = 4630
Then, 4630 - 3591.72 = 1038.28
Then, 1038.28 + 385.670 = 1423.95 ≈ 1424
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1424 million (corresponding to the option: 1424 million)