Question

question 4 of 10
pedro buys lunch at school every day. he always gets pizza when it is available. the cafeteria has pizza about 80% of the time.
pedro runs a simulation to model this using a random number generator. he assigns these digits to the possible outcomes for each day of the week:

• let 0 and 1 = no pizza available
• let 2, 3, 4, 5, 6, 7, 8, and 9 = pizza available

the table shows the results of the simulation.

95032	47150	71709	38889	94007
35013	57890	72924	19365	47879

what is the estimated probability that pedro will eat pizza for lunch every day next week?
a. 0.7
b. 0.3
c. 0.4
d. 0.0

Explanation:

Step1: Count total simulations

There are 10 simulation groups (5 in first row, 5 in second row), so total trials \( n = 10 \).

Step2: Identify all-pizza days

Check each 5 - digit number (each represents a week). A week has all pizza if no 0 or 1.

• 95032: has 0 → no
• 47150: has 1 and 0 → no
• 71709: has 1 and 0 → no
• 38889: no 0/1 → yes
• 94007: has 0 → no
• 35013: has 0 and 1 → no
• 57890: has 0 → no
• 72924: no 0/1 → yes
• 19365: has 1 → no
• 47879: no 0/1 → yes

Count of all - pizza weeks: 3 (38889, 72924, 47879).

Step3: Calculate probability

Probability \( P=\frac{\text{Number of all - pizza weeks}}{\text{Total weeks}}=\frac{3}{10} = 0.3 \).

Answer:

B. 0.3