Question

g.pr.10.2 (mc)

the table below shows the number of students who are majoring in engineering and / or taking calculus in their freshman year of college. find \\(p(\text{not calculus} \mid \text{engineering})\\)

\\(\

$$\begin{array}{|l|l|l|l|}\\hline & \\text{engineering} & \\text{not engineering} & \\text{total} \\\\\\hline \\text{calculus} & 980 & 470 & 1450 \\\\\\hline \\text{not calculus} & 250 & 2330 & 2580 \\\\\\hline \\text{total} & 1230 & 2800 & 4030 \\\\\\hline\\end{array}$$

\\)

• 20.3%
• 8.6%
• 64%
• 18%

Explanation:

Identify the given values from the table

$$
LATEXBLOCK0
$$

Apply the conditional probability formula

$$ P(\text{Not Calculus} \mid \text{Engineering}) = \frac{n(\text{Not Calculus} \cap \text{Engineering})}{n(\text{Engineering})} = \frac{250}{1230} $$

Calculate the percentage

$$ \frac{250}{1230} \approx 0.20325 \approx 20.3\% $$

Answer:

• (A) 20.3% (Correct answer)
• (B) 8.6%
• (C) 64%
• (D) 18%