Question

polydactyly is a condition in which someone is born with extra fingers &/or toes. it can be an inherited trait that is expressed if the offspring receives a dominant allele from one or both parents. if one parent is heterozygous for polydactyly (pp), and the other parent does not have polydactyly (pp), what are the chances that they will have a child that has extra fingers &/or toes? work the punnett square and then choose the correct answer based on your results. types of polydactyly

Explanation:

Step1: Determine Parental Alleles

One parent: Pp (heterozygous), so alleles are P and p.
Other parent: pp (homozygous recessive), so alleles are p and p.

Step2: Create Punnett Square

	P	p
p	Pp	pp

Step3: Analyze Offspring Genotypes

From the square, genotypes are Pp (2) and pp (2).
Polydactyly is dominant (expressed with P), so Pp offspring have the trait.

Step4: Calculate Probability

Number of Pp offspring: 2. Total offspring: 4.
Probability = $\frac{2}{4} = 50\%$ (or $\frac{1}{2}$).

Answer:

The chance is 50% (or $\frac{1}{2}$).