Question

a plant heterozygous for yellow seeds is crossed with a plant homozygous for green seeds. use the punnett square to predict the phenotype of the offspring. 1 2 yellow 3 green 4 done

Explanation:

Step1: Determine Genotypes

The heterozygous yellow - seeded plant has genotype \(Yy\) (since yellow is dominant, let \(Y\) be the allele for yellow and \(y\) for green), and the homozygous green - seeded plant has genotype \(yy\). When we set up the Punnett square, the top row (from the heterozygous plant) has alleles \(Y\) and \(y\), and the left - hand column (from the homozygous plant) has two \(y\) alleles.

Step2: Fill Punnett Square

• For cell 1 (intersection of \(Y\) and \(y\)): The genotype is \(Yy\). Since \(Y\) is dominant for yellow, the phenotype is yellow.
• For cell 2 (intersection of \(y\) and \(y\)): The genotype is \(yy\)? Wait, no. Wait, the top row is \(Y\) and \(y\) (from \(Yy\) plant), and the left column is \(y\) and \(y\) (from \(yy\) plant). So cell 1: \(Y\times y = Yy\) (yellow), cell 2: \(y\times y=yy\)? No, wait, no. Wait, the top row is the alleles from the first parent (\(Yy\)), so the top two cells are \(Y\) (first column) and \(y\) (second column). The left column is the alleles from the second parent (\(yy\)), so both rows on the left are \(y\). So cell 1: \(Y\) (top) and \(y\) (left) → \(Yy\) (yellow). Cell 2: \(y\) (top) and \(y\) (left) → \(yy\) (green). Cell 3: \(Y\) (top) and \(y\) (left) → \(Yy\) (yellow). Cell 4: \(y\) (top) and \(y\) (left) → \(yy\) (green). Wait, but let's re - check. The first parent: \(Yy\) (produces gametes \(Y\) and \(y\)). Second parent: \(yy\) (produces gametes \(y\) and \(y\)). So Punnett square:

	\(Y\)	\(y\)
\(y\)	\(Yy\) (yellow)	\(yy\) (green)

So for cell 1 (\(Yy\)): phenotype is yellow. For cell 2 (\(yy\)): phenotype is green. For cell 3 (\(Yy\)): phenotype is yellow. For cell 4 (\(yy\)): phenotype is green. But looking at the dropdown, for option 1 (cell 1), the phenotype is yellow. For option 4 (cell 4), the phenotype is green. Wait, the first dropdown (1) should be yellow, and the second dropdown (4) should be green. But let's focus on the first part. Let's assume the question is about cell 1 and cell 4. But the initial problem has two dropdowns, 1 and 4. Let's solve for dropdown 1 first. The genotype of cell 1 is \(Yy\), so phenotype is yellow. For dropdown 4, genotype is \(yy\), so phenotype is green. But let's go step by step.

First, for the first dropdown (1): The allele from the top is \(Y\) and from the left is \(y\), so genotype \(Yy\). Since yellow (\(Y\)) is dominant, phenotype is yellow.

For the fourth dropdown (4): The allele from the top is \(y\) and from the left is \(y\), so genotype \(yy\). Since green is recessive and expressed when homozygous, phenotype is green.

Answer:

For dropdown 1: yellow; For dropdown 4: green