Question

a plant heterozygous for yellow seeds is crossed with a plant homozygous for green seeds. use the punnett square to predict the phenotype of the offspring. 1 yellow 2 green 3 4 yellow green

Explanation:

Step1: Determine Genotypes

The heterozygous yellow - seeded plant has genotype \(Yy\) (since yellow is dominant, let \(Y\) be the allele for yellow and \(y\) for green), and the homozygous green - seeded plant has genotype \(yy\).

Step2: Analyze Punnett Square Cells

• For cell 3: The top allele is \(Y\) (from the heterozygous parent) and the side allele is \(y\) (from the homozygous parent), so the genotype is \(Yy\). Since \(Y\) is dominant for yellow, the phenotype is yellow.
• For cell 4: The top allele is \(y\) and the side allele is \(y\), so the genotype is \(yy\), and the phenotype is green. But we are focusing on cell 3 here. Since the genotype of cell 3 is \(Yy\), and yellow (\(Y\)) is dominant over green (\(y\)), the phenotype of cell 3 is yellow.

Answer:

yellow