Question

part a- deducing phenotypes and genotypes of selfed parents mendel studied pea plants dihybrid for seed shape (round versus wrinkled) and seed color (yellow versus green). recall that - the round allele (r) is dominant to the wrinkled allele (r) and - the yellow allele (y) is dominant to the green allele (y). the table below shows the f₁ progeny that result from selfing four different parent pea plants. use the phenotypes of the f₁ progeny to deduce the genotype and phenotype of each parent plant. complete the table by dragging the correct label to the appropriate location. labels can be used once, more than once, or not at all. 4 view available hint(s) table and diagram related to pea plant genetics, including parent phenotype, parent genotype, f₁ progeny phenotypes from selfed parent columns, and various labels and pea images

Explanation:

Step1: Analyze Plant 1 Progeny

Plant 1's F₁ progeny has two green (yy, since green is recessive) and two... Wait, the progeny shown: let's recall Mendelian genetics. Round (R) dominant, wrinkled (r); yellow (Y) dominant, green (y). For seed color: if progeny has green (yy), parent must have y. For seed shape: need to see ratios. But maybe the parent phenotypes: Let's check each plant.

Plant 1: F₁ progeny (from selfed parent) – let's assume the parent's genotype leads to progeny. Wait, the problem is about deducing parent phenotype from F₁. Let's take Plant 4: F₁ has only green (so parent must be yy for color) and maybe wrinkled? Wait, no, let's go step by step.

Wait, the top has genotypes like rryy, Rryy, etc. Let's match:

- Plant 4: F₁ progeny is only green (so color is yy, recessive). So parent's color allele is yy. For shape: if progeny is all wrinkled? Wait, no, the F₁ for Plant 4 is one green (so maybe all green, meaning parent is yy for color, and maybe rr for shape? Wait, no, let's think of Mendel's dihybrid.

Wait, the key is:

- Round (R) > wrinkled (r)
- Yellow (Y) > green (y)

So:

- Plant 1: F₁ progeny – let's say the two green (yy) and two... Wait, maybe the parent phenotypes:

Plant 1: F₁ has green (yy) and maybe wrinkled? Wait, no, the table:

Plant 1: Parent phenotype (G2), Parent genotype (G1), F1 progeny phenotypes.

Wait, maybe the correct deductions:

Plant 1: F₁ has two green (yy) and two... Wait, maybe the parent is wrinkled green? No, let's use the genotypes.

Wait, the top blue boxes are genotypes: rryy, Rryy, RrYy, etc.

Let's take Plant 4: F₁ progeny is only green (so color is yy), and if all are wrinkled? Wait, no, the F₁ for Plant 4 is one green (so maybe all green, so parent is yy for color, and rr for shape? So parent phenotype: wrinkled green (rryy)? Wait, no, rryy is wrinkled green.

Wait, maybe the correct parent phenotypes:

Plant 1: Let's see F₁ progeny – two green (yy) and two... Wait, maybe the parent is wrinkled green? No, let's check each:

Plant 1: F₁ progeny (from selfed parent) – suppose the parent is Rryy (round green). Selfing Rryy: Rr x Rr → 3 round:1 wrinkled; yy x yy → all green. So F₁ would be round green and wrinkled green. But the F₁ shown for Plant 1: two green (maybe wrinkled and round green? Wait, the image shows two green (one wrinkled, one round? No, the icons: green with wrinkled? Wait, maybe the progeny for Plant 1 is wrinkled green and round green? So parent is Rryy (round green), so parent phenotype: round green.

Plant 2: F₁ has green and yellow (so Yy), and round and wrinkled? Wait, F₁ has two green and two yellow, two round and two wrinkled? So parent is RrYy (round yellow), selfing gives 9:3:3:1. So F₁ has yellow (Y_) and green (yy), round (R_) and wrinkled (rr). So parent phenotype: round yellow.

Plant 3: F₁ has green and yellow (Yy) and maybe round and wrinkled? Wait, F₁ has one green and one yellow, one round and one wrinkled? So parent is RrYy? No, maybe Rryy? No, wait, Plant 3's F₁ has green and yellow, so Yy, so parent has Y and y. So parent is RrYy? No, maybe RRYy? No, let's think again.

Wait, maybe the correct parent phenotypes:

Plant 1: Parent phenotype: wrinkled green (rryy)? No, selfing rryy gives all rryy (wrinkled green). But F₁ for Plant 1 has two green (maybe wrinkled and round? No, rryy selfed is all rryy. So maybe Plant 1's parent is Rryy (round green): selfing Rryy → Rr x Rr (3 round:1 wrinkled), yy x yy (all green). So F₁: round green (R_yy) and wrinkled green (rryy). So parent phenotype: round green.

Plant 2: Parent is RrYy (round yellow): selfing gives 9 round yellow, 3 round green, 3 wrinkled yellow, 1 wrinkled green. So F₁ has yellow (Y_) and green (yy), round (R_) and wrinkled (rr). So parent phenotype: round yellow.

Plant 3: Parent is RRYy (round yellow)? No, selfing RRYy: RR x RR (all round), Yy x Yy (3 yellow:1 green). So F₁ would be round yellow and round green. But Plant 3's F₁ has green and yellow, round and wrinkled? No, maybe parent is RrYY (round yellow): selfing Rr x Rr (3 round:1 wrinkled), YY x YY (all yellow). So F₁: round yellow and wrinkled yellow. But Plant 3's F₁ has green, so no. Wait, maybe I'm overcomplicating.

Wait, the problem is to drag labels, but since it's a deduction, let's summarize:

Using Mendelian dominance (R > r, Y > y), we deduce parent phenotypes by F₁ progeny:

- Plant 1: F₁ has green (yy) and round/wrinkled? If F₁ has green (recessive), parent must have y. If F₁ has both round and wrinkled, parent is Rr. So parent phenotype: round green (Rryy).

- Plant 2: F₁ has yellow (Y_) and green (yy), round (R_) and wrinkled (rr) → parent is RrYy (round yellow).

- Plant 3: F₁ has yellow (Y_) and green (yy), round (R_) and wrinkled (rr)? No, maybe parent is RRYy (round yellow) but no, F₁ has green, so Yy. Wait, maybe Plant 3's parent is RrYy? No, same as Plant 2. Wait, maybe the key is:

Plant 4: F₁ has only green (yy) and all wrinkled (rr) → parent is rryy (wrinkled green).

So the parent phenotypes:

Plant 1: round green

Plant 2: round yellow

Plant 3: wrinkled yellow? No, wait, no.

Wait, maybe the correct answers (assuming the drag-and-drop labels):

But since the problem is to deduce, let's conclude with the Mendelian genetics application.

Step2: Final Deduction

After analyzing each plant's F₁ progeny using dominant/recessive alleles (R > r, Y > y), we match parent phenotypes to their F₁ ratios.

Answer:

(Assuming the correct parent phenotypes after deduction, e.g., Plant 4: wrinkled green, Plant 1: round green, etc. But since the exact drag-and-drop isn't fully visible, the key is applying Mendelian genetics (Biology subfield) to deduce parent phenotypes from F₁ progeny.)

(Note: The subfield is Biology (Natural Science) as it involves Mendelian genetics and pea plant traits.)