Question

ordering rational numbers order the numbers from least to greatest.

1. $-3.1$, $-4$, $-\frac{10}{3}$, $-3\frac{3}{4}$, $-3.7$
2. $3$, $-2\frac{2}{3}$, $0$, $-\frac{5}{4}$, $-0.85$
3. $\frac{3}{10}$, $-1\frac{1}{3}$, $0.02$, $1$, $-0.5$
4. $-4.25$, $1$, $-\frac{22}{5}$, $-4\frac{7}{8}$, $-3$

Explanation:

Step1: Convert to decimals

Convert each number to decimal for easier comparison:

• \(-3.1\) is already a decimal.
• \(-4\) is an integer, decimal form is \(-4.0\).
• \(-\frac{10}{3} \approx -3.333\) (since \(10\div3\approx3.333\)).
• \(-3\frac{3}{4} = -3.75\) (because \(\frac{3}{4}=0.75\)).
• \(-3.7\) is already a decimal.

Step2: Order from least to greatest

Now, order the decimals from least (most negative) to greatest:

• \(-4.0\) (which is \(-4\)) is the least.
• Next is \(-3.75\) (which is \(-3\frac{3}{4}\)).
• Then \(-3.7\).
• Then \(-3.333\) (which is \(-\frac{10}{3}\)).
• Then \(-3.1\).

So the order from least to greatest is \(-4, -3\frac{3}{4}, -3.7, -\frac{10}{3}, -3.1\).

Answer:

\(-4, -3\frac{3}{4}, -3.7, -\frac{10}{3}, -3.1\)