Question

one hundred thirty people were asked to determine how many cups of fruit and water they consumed per day. the results are shown in the frequency table.

	≤ 2 cups of fruit	> 2 cups of fruit	total
> 4 cups of water	18	30	48
total	80	50	130

identify the conditional relative frequency by row. round to the nearest percent.
the conditional relative frequency that someone ate more than 2 cups of fruit, given the person drank less than or equal to 4 cups of water is approximately dropdown.
the conditional relative frequency that someone ate less than or equal to 2 cups of fruit, given the person drank more than 4 cups of water is approximately dropdown with options 14%, 23%, 38%, 60%.

Explanation:

First Conditional Relative Frequency:

Step1: Identify the row and cell.

For "someone ate more than 2 cups of fruit, given the person drank less than or equal to 4 cups of water", the row is "≤ 4 Cups of Water", and the cell for "> 2 Cups of Fruit" is 20. The total of this row is 82.

Step2: Calculate the conditional relative frequency.

The formula is $\frac{\text{Frequency of > 2 Cups of Fruit and ≤ 4 Cups of Water}}{\text{Total of ≤ 4 Cups of Water row}}$. So, $\frac{20}{82} \approx 0.2439$, which is approximately 24% (but let's check the second part first).

Second Conditional Relative Frequency:

Step1: Identify the row and cell.

For "someone ate less than or equal to 2 cups of fruit, given the person drank more than 4 cups of water", the row is "> 4 Cups of Water", and the cell for "≤ 2 Cups of Fruit" is 18. The total of this row is 48.

Step2: Calculate the conditional relative frequency.

Using the formula $\frac{\text{Frequency of ≤ 2 Cups of Fruit and > 4 Cups of Water}}{\text{Total of > 4 Cups of Water row}}$, we get $\frac{18}{48} = 0.375$, which is 37.5% ≈ 38%.

Now, going back to the first one: $\frac{20}{82} \approx 0.2439 \approx 24\%$, but let's check the options (wait, the first part's options aren't shown, but the second part's options include 38%, which matches our calculation for the second one. Let's re-express:

For the first conditional relative frequency (ate more than 2 cups of fruit, given drank ≤ 4 cups of water):
Number of people who ate >2 cups of fruit and drank ≤4 cups of water: 20
Total number of people who drank ≤4 cups of water: 82
So, $20 \div 82 \approx 0.2439 \approx 24\%$ (but maybe the options have 24% or similar, but since the second part's correct answer is 38% (from 18/48 = 0.375 ≈ 38%)

Answer:

First conditional relative frequency (ate more than 2 cups of fruit, given drank ≤4 cups of water): Approximately 24% (calculation: $\frac{20}{82} \approx 24\%$)
Second conditional relative frequency (ate ≤2 cups of fruit, given drank >4 cups of water): 38% (calculation: $\frac{18}{48} = 0.375 \approx 38\%$)

(Assuming the first part's answer is around 24% and the second is 38%, so for the second dropdown, the answer is 38%.)