Question

normal ladybug: cggacactgctctcccaagagtatcagtacctctttagaagacctgaattcattctctt
dotless ladybug: cggacactgctctcccaagagtatcagtcctctttagaagacctgaattcattctctt

1. dotlessness is a recessive trait. cross two ladybugs who have dots, each of which has a dotless

parent, (ls3 - 3)
parent genotypes (use the letters t and t): _t_ x _t_
what is the probability of having a dotless ladybug? _25_%
what is the probability of having a ladybug with dots? _75_%

Explanation:

Step1: Determine the genotypes of the parents

Since each parent has a dotless parent (tt), and they have dots (so they are not tt), their genotypes must be Tt.

Step2: Create a Punnett square

	T	t
t	Tt	tt

Step3: Calculate the probability of having a ladybug with dots

The genotypes for having dots are TT and Tt. There are 3 out of 4 possible genotypes (TT, Tt, Tt) that result in dots. So the probability is $\frac{3}{4}=0.75 = 75\%$.

Answer:

75%