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mrs. kramer has a stack of papers to grade every day. on the past 5 day…

Question

mrs. kramer has a stack of papers to grade every day. on the past 5 days, she has graded: 20 papers 46 papers 90 papers 49 papers 95 papers what was the mean absolute deviation of the numbers of papers graded? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): papers

Explanation:

Step1: Calcular la media

La media $\bar{x}$ de un conjunto de datos $x_1,x_2,\cdots,x_n$ se calcula como $\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}$. Aquí, $n = 5$, $x_1=20$, $x_2 = 46$, $x_3=90$, $x_4=49$, $x_5=95$.

$\bar{x}=\frac{20 + 46+90+49+95}{5}=\frac{300}{5}=60$

Step2: Calcular las desviaciones absolutas

La desviación absoluta de cada valor $x_i$ con respecto a la media $\bar{x}$ es $|x_i-\bar{x}|$.

Para $x_1 = 20$: $|20 - 60|=40$

Para $x_2 = 46$: $|46-60| = 14$

Para $x_3=90$: $|90 - 60|=30$

Para $x_4=49$: $|49-60| = 11$

Para $x_5=95$: $|95 - 60|=35$

Step3: Calcular la media de las desviaciones absolutas (MAD)

$MAD=\frac{40+14 + 30+11+35}{5}=\frac{130}{5}=26$

Answer:

$26$