Question

in a monohybrid cross between two true - breeding parents that both exhibit the dominant phenotype, ___ percent of the offspring will exhibit the recessive phenotype. 25 100 50 0

Explanation:

Step1: Analyze the genotypes of true - breeding dominant parents

True - breeding dominant parents have homozygous dominant genotypes. Let the allele for the dominant trait be \(A\) and for the recessive trait be \(a\). The genotype of each parent is \(AA\).

Step2: Perform the cross

When \(AA\times AA\), using the Punnett square method (or simple allele combination rules), all offspring will have the genotype \(AA\).

Step3: Determine the phenotype

Since the genotype of all offspring is \(AA\), and \(A\) is the dominant allele, all offspring will exhibit the dominant phenotype. So the percentage of offspring with the recessive phenotype is \(0\).

Answer:

\(0\)