Question

the momentum of an object is determined to be ( 7.2\times10^{-3}\text{ kg}cdot\text{m/s} ). express this quantity as provided or use any equivalent unit. (note: ( 1\text{ kg}=1000\text{ g} ))

Explanation:

Step1: Convert kg to g

Since \(1\space kg = 1000\space g=10^{3}\space g\), we can rewrite the given momentum \(p = 7.2\times10^{-3}\space kg\cdot m/s\). Substitute \(kg\) with \(10^{3}\space g\): \(p=7.2\times 10^{-3}\times10^{3}\space g\cdot m/s\)
Using the rule of exponents \(a^{m}\times a^{n}=a^{m + n}\), here \(m=-3\) and \(n = 3\), so \(7.2\times 10^{-3}\times10^{3}=7.2\times10^{-3 + 3}\)

Step2: Simplify the exponent

\(-3+3 = 0\), and \(a^{0}=1\) (\(a
eq0\)), so \(7.2\times10^{-3 + 3}=7.2\times10^{0}\)
Since \(10^{0}=1\), then \(7.2\times10^{0}=7.2\)

Answer:

Value: \(7.2\), Units: \(g\cdot m/s\)