Question

the momentum of an object is determined to be ( 7.2 \times 10^{-3} , \text{kg} cdot \text{m/s} ). express this quantity as provided or use any equivalent unit. (note: ( 1 , \text{kg} = 1000 , \text{g} ))

Explanation:

Step1: Recall unit conversion for mass

We know that \(1\space kg = 1000\space g=1\times10^{3}\space g\). So we can convert the mass unit from \(kg\) to \(g\) in the momentum unit.
The given momentum is \(7.2\times 10^{- 3}\space kg\cdot m/s\). Substitute \(kg\) with \(1\times10^{3}\space g\):
\(7.2\times 10^{-3}\space kg\cdot m/s=7.2\times 10^{-3}\times(1\times 10^{3}\space g)\cdot m/s\)

Step2: Simplify the expression

Using the rule of exponents \(a^{m}\times a^{n}=a^{m + n}\), we have:
\(7.2\times10^{-3}\times1\times 10^{3}\space g\cdot m/s=7.2\times(10^{-3 + 3})\space g\cdot m/s=7.2\times10^{0}\space g\cdot m/s\)
Since \(10^{0} = 1\), this simplifies to \(7.2\space g\cdot m/s\)

Answer:

\(7.2\space g\cdot m/s\) (or \(7.2\times 10^{-3}\space kg\cdot m/s\))