Question

mixed punnett square practice

1. brown hair is dominant to blonde hair. cross a woman who is heterozygous for brown hair with a man who is heterozygous. what percentage of their children will have brown hair?

Explanation:

Step1: Determine the genotypes

Let \( B \) represent the allele for brown hair (dominant) and \( b \) represent the allele for blonde hair (recessive). The woman is heterozygous (\( Bb \)) and the man is also heterozygous (\( Bb \)).

Step2: Set up the Punnett square

	\( B \)	\( b \)
\( b \)	\( Bb \)	\( bb \)

Step3: Analyze the genotypes for brown hair

Genotypes \( BB \), \( Bb \), and \( Bb \) result in brown hair. There are 3 out of 4 possible genotypes that give brown hair.

Step4: Calculate the percentage

The percentage is \(\frac{3}{4}\times100\% = 75\%\)

Answer:

75%