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in mice, the gene for tail length has two alleles. a long tail is domin…

Question

in mice, the gene for tail length has two alleles. a long tail is dominant to a short tail. if a long-tailed mouse that is heterozygous mates with a short-tailed mouse, what are the chances of having offspring with short tails? (1 point) 25% 50% 75% 100%

Explanation:

Step1: Determine the genotypes

Let \( T \) represent the allele for long tail (dominant) and \( t \) represent the allele for short tail (recessive). The heterozygous long - tailed mouse has genotype \( Tt \), and the short - tailed mouse has genotype \( tt \).

Step2: Set up the Punnett square

\( T \)\( t \)
\( t \)\( Tt \)\( tt \)

Step3: Calculate the probability

Out of the 4 possible offspring genotypes (\( Tt, Tt, tt, tt \)), 2 are \( tt \) (short - tailed). The probability is \( \frac{2}{4}=\frac{1}{2} = 50\%\)

Answer:

50%