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Question
mariana has a cell phone plan that has a monthly charge plus a per text fee. the table shows mariana’s monthly bill for october, november, and december along with the number of texts she sent during these months.
| month | number of texts | monthly bill (dollars) |
|---|---|---|
| november | 118 | 40.90 |
| december | 200 | 45.00 |
stat 1
enter in number of text on the l₁
enter in monthly bill on the l₂
stat → calc 4
enter down thru calculate
determine the y-intercept from the table of values and write it as an ordered pair.
y-intercept = (□ , □)
Step1: Define the linear model
Let the number of texts be \( x \) and the monthly bill be \( y \). The linear equation is \( y = mx + b \), where \( m \) is the slope (per text fee) and \( b \) is the y - intercept (monthly charge).
Step2: Calculate the slope \( m \)
Using two points, say \((x_1,y_1)=(45, 37.25)\) and \((x_2,y_2)=(200, 45.00)\). The slope formula is \( m=\frac{y_2 - y_1}{x_2 - x_1}\)
\(m=\frac{45.00 - 37.25}{200 - 45}=\frac{7.75}{155}=0.05\)
Step3: Find the y - intercept \( b \)
Substitute \( x = 45\), \( y = 37.25\) and \( m = 0.05\) into \( y=mx + b\)
\(37.25=0.05\times45 + b\)
\(37.25 = 2.25+b\)
Subtract 2.25 from both sides: \(b=37.25 - 2.25=35\)
The y - intercept occurs when \( x = 0\) (since in the linear equation \( y=mx + b\), when \( x = 0\), \( y=b\)). So the ordered pair for the y - intercept is \((0, 35)\)
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\(y\)-intercept \(=(0, 35)\)