Question

1. a leaky faucet loses 0.35 l of water in an hour. how long will take for the faucet to lose 21 l? do not use a calculator and show all your work. i

Explanation:

Step1: Define the problem

We know the rate of water loss is \(0.35\) L per hour, and we need to find the time \(t\) (in hours) when the total water loss is \(21\) L. The formula relating rate (\(r\)), time (\(t\)), and amount (\(A\)) is \(A = r\times t\), so we can solve for \(t\) as \(t=\frac{A}{r}\).

Step2: Substitute the values

Here, \(A = 21\) L and \(r=0.35\) L/hour. So \(t=\frac{21}{0.35}\). To simplify this division, we can multiply numerator and denominator by \(100\) to eliminate the decimal: \(\frac{21\times100}{0.35\times100}=\frac{2100}{35}\).

Step3: Perform the division

We know that \(35\times60 = 2100\) (because \(35\times6 = 210\), so \(35\times60=2100\)). So \(\frac{2100}{35}=60\).

Answer:

60 hours