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Question
l8 - practice test
score: 95/100 answered: 19/20
question 20
laura is bowling 5 games. her first 4 scores were 116, 80, 111, and 94.
to end up with an average score of at least 116, what is the lowest score laura will need in the fifth game?
check answer
Step1: Calculate the total score needed for 5 games
The formula for the average is $\text{Average}=\frac{\text{Total Score}}{\text{Number of Games}}$.
If the average score is at least 116 for 5 games, then the total score needed is $116\times5 = 580$.
Step2: Calculate the sum of the first 4 scores
The sum of the first 4 scores is $116 + 80+111 + 94=401$.
Step3: Find the score needed in the fifth game
Let $x$ be the score in the fifth game.
We know that $401+x\geq580$.
Solving for $x$, we get $x\geq580 - 401$.
$x\geq179$.
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179