Question

john’s dog has floppy ears. the gene for floppy ears is recessive (f). john’s dog is expecting puppies from mating with a dog that is homozygous dominant and is homozygous recessive for this. what is the probability that any of the dogs will have floppy ears?
probability of floppy ears
chart (punnett square) is present but empty

Explanation:

Step1: Determine Genotypes

John's dog (recessive, floppy ears) has genotype \( ff \). The mating dog is homozygous dominant, so genotype \( FF \).

Step2: Set Up Punnett Square

	\( F \)	\( F \)
\( f \)	\( Ff \)	\( Ff \)

Step3: Analyze Offspring Genotypes

All offspring have genotype \( Ff \). Since floppy ears (\( f \)) is recessive, \( Ff \) shows the dominant (non - floppy) trait. So the number of offspring with floppy ears is 0 out of 4.

Step4: Calculate Probability

Probability \(=\frac{\text{Number of floppy - eared offspring}}{\text{Total offspring}}=\frac{0}{4} = 0\).

Answer:

The probability that any of the dogs will have floppy ears is \( 0 \) (or \( 0\% \)).