Question

1. jay is on a fishing trip and decides to swing a 0.028-kg fishing-line weight around on the end of a 0.75-m piece of fishing line. the weight makes one revolution in 1.2 s. what is the magnitude of the force exerted by the string on the weight?

Explanation:

Step1: Calculate angular velocity

$\omega = \frac{2\pi}{T} = \frac{2\pi}{1.2} \approx 5.236 \, \text{rad/s}$

Step2: Compute centripetal force

$F = m\omega^2 r = 0.028 \times (5.236)^2 \times 0.75$
First calculate $\omega^2$: $5.236^2 \approx 27.42$
Then $0.028 \times 27.42 \approx 0.7678$
Finally $0.7678 \times 0.75 \approx 0.576$

Answer:

0.58 N (rounded to two decimal places)