Question

if the heterozygous, ww, is crossed with a homozygous dominant, ww, then the probability of having a homozygous recessive offspring is

Explanation:

Step1: Analyze the cross

When \(Ww\) (heterozygous) is crossed with \(WW\) (homozygous dominant), the possible gametes are \(W\) and \(w\) from \(Ww\), and \(W\) from \(WW\).

Step2: Use Punnett square

The Punnett - square cross is \(Ww\times WW\). The possible genotypes of the offspring are \(WW\) and \(Ww\).

Step3: Calculate the probability

The genotypes of the offspring are \(WW:Ww = 1:1\). There is no \(ww\) (homozygous recessive) offspring.

Answer:

\(0\%\)