Question

here are the ages (in years) of 8 professors at a college.
61, 42, 61, 34, 49, 44, 36, 47
what is the percentage of these professors who are younger than 45?

Explanation:

Step1: Count the number of professors younger than 45

The ages are \(61,42,61,34,49,44,36,47\). The ages younger than 45 are \(42,34,44,36\). So there are \(n = 4\) professors younger than 45.

Step2: Calculate the percentage

The formula for percentage is \(\text{Percentage}=\frac{\text{Number of favorable cases}}{\text{Total number of cases}}\times100\%\). The total number of professors is \(N = 8\). Then \(\text{Percentage}=\frac{4}{8}\times100\%\).
Since \(\frac{4}{8}=\frac{1}{2}=0.5\), then \(0.5\times100\% = 50\%\)

Answer:

\(50\%\)