Question

in a group of pea plants, some individuals have round peas and others have wrinkled peas. in this group, the gene for the pea shape trait has two alleles. the allele for wrinkled peas (e) is recessive to the allele for round peas (e). complete the punnett square to show all possible genotypes of the offspring from a cross between two pea plants: parent 1 is heterozygous, and parent 2 is homozygous recessive. parent 2 two empty squares parent 1 two empty squares, and a punnett square with empty cells

Explanation:

Step1: Determine Genotypes of Parents

Parent 1 is heterozygous for pea shape, so its genotype is \( Ee \). This means it can produce two types of gametes: \( E \) and \( e \). Parent 2 is homozygous recessive, so its genotype is \( ee \), and it can only produce gametes with the \( e \) allele. So, the top row (Parent 2's gametes) will have \( e \) and \( e \), and the left column (Parent 1's gametes) will have \( E \) and \( e \).

Step2: Fill in the Punnett Square

• Top - left cell (cross \( E \) from Parent 1 and \( e \) from Parent 2): Genotype is \( Ee \).
• Top - right cell (cross \( E \) from Parent 1 and \( e \) from Parent 2): Genotype is \( Ee \).
• Bottom - left cell (cross \( e \) from Parent 1 and \( e \) from Parent 2): Genotype is \( ee \).
• Bottom - right cell (cross \( e \) from Parent 1 and \( e \) from Parent 2): Genotype is \( ee \).

So the Punnett square should be filled as follows (rows for Parent 1's gametes, columns for Parent 2's gametes):

Parent 2 \ Parent 1	\( E \)	\( e \)
\( e \)	\( ee \)	\( ee \)

Answer:

The Punnett square filled with genotypes:

• Parent 2's gametes (top row): \( e \), \( e \)
• Parent 1's gametes (left column): \( E \), \( e \)
• Top - left cell: \( Ee \)
• Top - right cell: \( Ee \)
• Bottom - left cell: \( ee \)
• Bottom - right cell: \( ee \)