Question

the graph shows the ages of different concertgoers who have back - stage passes. which statement is true about the graph? backstage passes a late arrival who is 21 years old with a back - stage pass will make the mean greater than the median. the two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age. the ages of concert - goers with backstage passes are skewed left, so the mean age is less than the median age. a concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.

Explanation:

Step1: Recall the properties of mean and median

The mean is affected by extreme values. The median is the middle - value when data is ordered.

Step2: Analyze each option

• Option 1: A 21 - year - old is not an extreme value compared to the overall data range (12 - 48). So, it won't make the mean greater than the median.
• Option 2: The two values above 40 are extreme values. Since the mean is affected by extreme values (pulled up) and the median is less affected, the mean age will be higher than the median age.
• Option 3: The data is skewed right (has a tail on the higher - value side), not left.
• Option 4: An 18 - year - old is not an extreme value (close to the lower - end of the data range which is 12). It won't pull the mean more than 2 years less than the median.

Answer:

The two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age.