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the given jar contains yellow (y), blue (b), and red (r) balls. anne ra…

Question

the given jar contains yellow (y), blue (b), and red (r) balls. anne randomly chooses a single ball from the can shown here. find the odds against the event. blue or yellow (b or y) state the odds against blue or yellow in lowest terms. the odds against blue or yellow are \boxed{} to \boxed{}. (type whole numbers.)

Explanation:

Step1: Count the total number of balls

There are \(3 + 1+1 + 3+3 = 11\) balls in total.

Step2: Count the number of non - (blue or yellow) balls

Non - (blue or yellow) balls are red balls. There are \(6\) red balls.

Step3: Count the number of (blue or yellow) balls

Number of blue balls \(= 4\), number of yellow balls \(=1\). So number of (blue or yellow) balls \(=4 + 1=5\).

Step4: Calculate the odds against the event

Odds against an event \(E\) is given by \(\frac{\text{Number of non - favorable outcomes}}{\text{Number of favorable outcomes}}\). Here, non - favorable outcomes (not blue or yellow) \(=6\), favorable outcomes (blue or yellow) \(=5\).

Answer:

The odds against blue or yellow are \(6\) to \(5\).