Question

give the probability that the spinner shown would land on (a) red, (b) yellow, and (c) green. assume all sectors of the spinner are the same size. (a) the probability that the spinner shown would land on red is \\(\frac{2}{3}\\). (type an integer or a simplified fraction.) (b) the probability that the spinner shown would land on yellow is \\(\square\\). (type an integer or a simplified fraction.)

Explanation:

Step1: Count total sectors

The spinner has 6 equal - sized sectors (4 red + 2 green, and 0 yellow). So total number of sectors \(n = 6\).

Step2: Count yellow sectors

From the spinner diagram, there are 0 sectors colored yellow. Let the number of yellow sectors be \(m = 0\).

Step3: Calculate probability

The probability of an event \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). For landing on yellow, the number of favorable outcomes (yellow sectors) is 0. So \(P(\text{yellow})=\frac{0}{6}=0\).

Answer:

\(0\)