Question

a genetic experiment involving peas yielded one sample of offspring consisting of 438 green peas and 120 yellow pea use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yello identify the null hypothesis, alternative hypothesis, test statistic, p - value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. use the p - value method and the normal distribution as an approximation to the binomial distribution. what are the null and alternative hypotheses? ○a. ( h_0:p = 0.24 ) ( h_1:plt0.24 ) ○b. ( h_0:p = 0.24 ) ( h_1:pgt0.24 ) ○c. ( h_0:p
eq0.24 ) ( h_1:pgt0.24 ) ○d. ( h_0:p = 0.24 ) ( h_1:p
eq0.24 ) ○e. ( h_0:p
eq0.24 ) ( h_1:p = 0.24 ) ○f. ( h_0:p
eq0.24 ) ( h_1:plt0.24 )

Explanation:

Step1: Determine the claim

The claim is that \(p = 0.24\). The null hypothesis \(H_0\) is the statement of equality, so \(H_0:p = 0.24\).

Step2: Determine the alternative hypothesis

Since the problem is a two - tailed test (the claim is just a specific value, not a direction like greater than or less than), the alternative hypothesis \(H_1:p
eq0.24\)

Answer:

D. \(H_0:p = 0.24\), \(H_1:p
eq0.24\)