Question

a genetic experiment involving peas yielded one sample of offspring consisting of 435 green peas and 175 yellow peas. use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. identify the null hypothesis, alternative hypothesis, test statistic, p - value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. use the p - value method and the normal distribution as an approximation to the binomial distribution.

what are the null and alternative hypotheses?

○ a. ( h_0:p = 0.26 )
( h_1:p
eq0.26 )
○ b. ( h_0:p
eq0.26 )
( h_1:p > 0.26 )
○ c. ( h_0:p
eq0.26 )
( h_1:p < 0.26 )
○ d. ( h_0:p = 0.26 )
( h_1:p < 0.26 )
○ e. ( h_0:p
eq0.26 )
( h_1:p = 0.26 )
○ f. ( h_0:p = 0.26 )
( h_1:p > 0.26 )

Explanation:

Step1: Understand the null and alternative hypotheses

The null hypothesis \(H_0\) is a statement of equality. The claim is "26% of offspring peas will be yellow", so \(H_0: p = 0.26\). The alternative hypothesis \(H_1\) is the opposite of the null hypothesis for a two - tailed test (since we are just testing if the proportion is different from 0.26, not specifically greater or less).

Answer:

A. \(H_0: p = 0.26\), \(H_1: p
eq0.26\)