Question

frequency (number of students)
0 0 1 2 3 4 5 6 7 8 9 10
number of social media posts made
what was the median number of posts made?
answer attempt 1 out of 2
posts

Explanation:

Step1: Calculate total number of students

First, sum up the frequencies (number of students) for each number of posts:
For 0 posts: 5; 1 post: 3; 2 posts: 1; 3 posts: 2; 4 posts: 2; 5 posts: 2; 6 posts: 2; 7 posts: 0; 8 posts: 2; 9 posts: 4; 10 posts: 6.
Total = \( 5 + 3 + 1 + 2 + 2 + 2 + 2 + 0 + 2 + 4 + 6 = 29 \).

Step2: Find the median position

The median is the middle value. For \( n = 29 \) (odd), the median is at position \( \frac{n + 1}{2} = \frac{29 + 1}{2} = 15 \) (15th term when ordered).

Step3: Cumulative frequency to find the 15th term

Calculate cumulative frequencies:

• 0 posts: 5 (cumulative: 5)
• 1 post: 3 (cumulative: \( 5 + 3 = 8 \))
• 2 posts: 1 (cumulative: \( 8 + 1 = 9 \))
• 3 posts: 2 (cumulative: \( 9 + 2 = 11 \))
• 4 posts: 2 (cumulative: \( 11 + 2 = 13 \))
• 5 posts: 2 (cumulative: \( 13 + 2 = 15 \))

The 15th term falls in the "5 posts" category (since cumulative frequency reaches 15 at 5 posts).

Answer:

5