Question

find the value of $z_{\alpha}$
$\alpha = 0.26$
the value of $z_{0.26}$ is $\square$. (round to two decimal places as needed)

Explanation:

Step1: Find the area to the left of \(z_{\alpha}\)

The area to the left of \(z_{\alpha}\) is \(1-\alpha\). Given \(\alpha = 0.26\), then the area \(A=1 - 0.26=0.74\).

Step2: Use the standard normal distribution table (or z - table)

We look for the \(z\) - value corresponding to an area of \(0.74\) in the standard normal distribution table.
Looking up the value in the body of the standard - normal table (where the cumulative probability \(P(Z\leq z)\) is given), we find that for an area of \(0.74\), \(z\approx0.64\)

Answer:

\(0.64\)