Question

find the z - score that has 69.5% of the distributions area to its right.
the z - score is
(round to two decimal places as needed.)

Explanation:

Step1: Find area to the left

The total area under the standard - normal curve is 1. If 69.5% (or 0.695) of the area is to the right of the z - score, then the area to the left of the z - score is $1 - 0.695=0.305$.

Step2: Use the standard - normal table

We look up the value 0.305 in the body of the standard - normal (z - table). The closest value in the standard - normal table to 0.305 is 0.3050. The corresponding z - score for an area of 0.3050 is approximately $z=-0.51$.

Answer:

$-0.51$