Question

find the product. list the units.

1. $8\\ \mathrm{h} \times \frac{\\$9}{\mathrm{h}}$
2. $8\\ \mathrm{lb} \times \frac{\\$3.50}{\mathrm{lb}}$
3. $\frac{29}{2}\\ \mathrm{sec} \times \frac{60\\ \mathrm{mb}}{\mathrm{sec}}$
4. $\frac{3}{4}\\ \mathrm{h} \times \frac{19\\ \mathrm{mi}}{\frac{1}{4}\\ \mathrm{h}}$

write the ratio as a fraction in simplest form.

1. 25 to 45
2. $63:28$
3. $35\\ \mathrm{girls}:15\\ \mathrm{boys}$
4. $51\\ \mathrm{correct}:9\\ \mathrm{incorrect}$
5. $16\\ \mathrm{dogs}\\ \mathrm{to}\\ 12\\ \mathrm{cats}$
6. $2\frac{1}{3}\\ \mathrm{feet}:4\frac{1}{2}\\ \mathrm{feet}$

find the unit rate.

1. $180\\ \mathrm{miles}\\ \mathrm{in}\\ 3\\ \mathrm{hours}$
2. $256\\ \mathrm{miles}\\ \mathrm{per}\\ 8\\ \mathrm{gallons}$
3. $\\$9.60\\ \mathrm{for}\\ 4\\ \mathrm{pounds}$
4. $\\$4.80\\ \mathrm{for}\\ 6\\ \mathrm{cans}$
5. $297\\ \mathrm{words}\\ \mathrm{in}\\ 5.5\\ \mathrm{minutes}$
6. $21\frac{3}{4}\\ \mathrm{meters}\\ \mathrm{in}\\ 2\frac{1}{2}\\ \mathrm{hours}$

Explanation:

Problem 7:

Step1: Cancel units

The "h" units cancel out: \( 8\ \text{h} \times \frac{\$9}{\text{h}} = 8 \times \$9 \)

Step2: Multiply

\( 8 \times 9 = 72 \), so the result is \(\$72\)

Step1: Cancel units

The "lb" units cancel out: \( 8\ \text{lb} \times \frac{\$3.50}{\text{lb}} = 8 \times \$3.50 \)

Step2: Multiply

\( 8 \times 3.50 = 28 \), so the result is \(\$28\)

Step1: Cancel units

The "sec" units cancel out: \( \frac{29}{2}\ \text{sec} \times \frac{60\ \text{MB}}{\text{sec}} = \frac{29}{2} \times 60\ \text{MB} \)

Step2: Multiply

\( \frac{29}{2} \times 60 = 29 \times 30 = 870 \), so the result is \( 870\ \text{MB} \)

Answer:

\(\$72\)

Problem 8: