QUESTION IMAGE
Question
find and interpret the standard deviation of the data set.
- 18, 11, 15, 20, 16
- 78, 71, 68, 75, 46, 66
Problem 4:
Step 1: Find the mean (\(\mu\))
The data set is \( 18, 11, 15, 20, 16 \). The number of data points \( n = 5 \).
Step 2: Find the squared differences from the mean
For each data point \( x \), calculate \( (x-\mu)^2 \):
- For \( x = 18 \): \( (18 - 16)^2=2^2 = 4 \)
- For \( x = 11 \): \( (11 - 16)^2=(- 5)^2=25 \)
- For \( x = 15 \): \( (15 - 16)^2=(-1)^2 = 1 \)
- For \( x = 20 \): \( (20 - 16)^2=4^2=16 \)
- For \( x = 16 \): \( (16 - 16)^2=0^2 = 0 \)
Step 3: Find the variance (\(\sigma^2\))
Variance is the average of the squared differences.
Step 4: Find the standard deviation (\(\sigma\))
Standard deviation is the square root of the variance.
Problem 5:
Step 1: Find the mean (\(\mu\))
The data set is \( 78, 71, 68, 75, 46, 66 \). The number of data points \( n = 6 \).
Step 2: Find the squared differences from the mean
For each data point \( x \), calculate \( (x - \mu)^2 \):
- For \( x = 78 \): \( (78-67.33)^2=(10.67)^2\approx113.85 \)
- For \( x = 71 \): \( (71 - 67.33)^2=(3.67)^2\approx13.47 \)
- For \( x = 68 \): \( (68 - 67.33)^2=(0.67)^2\approx0.45 \)
- For \( x = 75 \): \( (75 - 67.33)^2=(7.67)^2\approx58.83 \)
- For \( x = 46 \): \( (46 - 67.33)^2=(-21.33)^2\approx455.07 \)
- For \( x = 66 \): \( (66 - 67.33)^2=(-1.33)^2\approx1.77 \)
Step 3: Find the variance (\(\sigma^2\))
Step 4: Find the standard deviation (\(\sigma\))
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The standard deviation is approximately \( 3.24 \). The data values are relatively close to the mean (average distance of about 3.24 from the mean).