find the indicated sum \$\\sum_{i=5}^{10} 11\$ \\(\\sum_{i=5}^{10} 11…

$find the indicated sum \$\\sum_{i=5}^{10} 11\$ \\(\\sum_{i=5}^{10} 11…$

find the indicated sum
\$\sum_{i=5}^{10} 11\$
\$\sum_{i=5}^{10} 11 = \square\$ (simplify your answer.)

The summation is from $ i = 5 $ to $ i = 10 $. To find the number of terms, we calculate $ 10 - 5 + 1 = 6 $ terms.

Since each term is 11, the sum is $ 11 \times 6 = 66 $.

66