Question

find the area under the standard normal curve in - between z = - 0.18 and z = 0.79
use the normal table and give answer using 4 decimal places.

Explanation:

Step1: Find the area for \(z = - 0.18\)

Using the standard normal table, the area to the left of \(z=-0.18\) is \(P(Z < - 0.18)=0.4286\)

Step2: Find the area for \(z = 0.79\)

Using the standard normal table, the area to the left of \(z = 0.79\) is \(P(Z < 0.79)=0.7852\)

Step3: Calculate the area between \(z=-0.18\) and \(z = 0.79\)

The area between two \(z\)-scores \(a\) and \(b\) (\(a < b\)) is \(P(a<Z < b)=P(Z < b)-P(Z < a)\)
Substitute \(a=-0.18\) and \(b = 0.79\)
\(P(-0.18<Z < 0.79)=P(Z < 0.79)-P(Z < - 0.18)\)
\(=0.7852 - 0.4286\)
\(=0.3566\)

Answer:

\(0.3566\)