Question

fill in the table using this function rule.
( y = 10x - 1 )
table with x values: -5, -1, 0, 1 and empty y cells

Explanation:

Step1: For \( x = -5 \)

Substitute \( x = -5 \) into \( y = 10x - 1 \).
\( y = 10\times(-5) - 1 = -50 - 1 = -51 \)

Step2: For \( x = -1 \)

Substitute \( x = -1 \) into \( y = 10x - 1 \).
\( y = 10\times(-1) - 1 = -10 - 1 = -11 \)

Step3: For \( x = 0 \)

Substitute \( x = 0 \) into \( y = 10x - 1 \).
\( y = 10\times0 - 1 = 0 - 1 = -1 \)

Step4: For \( x = 1 \)

Substitute \( x = 1 \) into \( y = 10x - 1 \).
\( y = 10\times1 - 1 = 10 - 1 = 9 \)

Answer:

When \( x = -5 \), \( y = -51 \); when \( x = -1 \), \( y = -11 \); when \( x = 0 \), \( y = -1 \); when \( x = 1 \), \( y = 9 \).

Filling the table:

\( x \)	\( y \)
-1	-11
0	-1
1	9