Question

examine the simple metabolic pathway in the figure below. a mutation results in a defective enzyme 1. which of the following results would be a consequence of that mutation?
enzyme 1
enzyme 2
a → b → c
○ an accumulation of a and no production of b and c
○ an accumulation of a and b and no production of c
○ an accumulation of b and no production of a and c
○ an accumulation of b and c and no production of a

Explanation:

In the metabolic pathway \( A \xrightarrow{\text{enzyme 1}} B \xrightarrow{\text{enzyme 2}} C \), enzyme 1 is responsible for converting \( A \) to \( B \). If enzyme 1 is defective, \( A \) cannot be converted to \( B \), so \( A \) will accumulate. Since \( B \) is not produced (because \( A \) can't be converted to \( B \)), enzyme 2 has no \( B \) to act on, so \( C \) will also not be produced.

Answer:

an accumulation of A and no production of B and C