Question

for every truck a police officer encounters she writes down t, for every car c, for every van v, and for every vehicle that is not a car, truck or van o (for \other\). estimate the probability that the next vehicle the police officer encounters is not a car, truck, or van.
tttcvoovcttccccccvo
(1 point)
\\(\frac{3}{19}\\)
\\(\frac{16}{19}\\)
\\(\frac{13}{19}\\)
\\(\frac{19}{3}\\)

Explanation:

Step1: Count total number of vehicles

Count the number of characters in the sequence \(TTTCVOOOVCTTTCCCCCCV O\). There are \(19\) characters. So \(n = 19\).

Step2: Count number of "other" vehicles

Count the number of \(O\)s. There are \(3\) \(O\)s. Let \(m\) be the number of "other" vehicles, so \(m=3\).

Step3: Calculate probability

The probability \(P\) of an event is given by \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, the probability that the vehicle is "other" (not \(C\), \(T\), or \(V\)) is \(P = \frac{m}{n}\). Substituting \(m = 3\) and \(n=19\), we get \(P=\frac{3}{19}\).

Answer:

\(\frac{3}{19}\)