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(a) for each event in the table, check the outcome(s) that are containe…

Question

(a) for each event in the table, check the outcome(s) that are contained in the event. then, in the last column, enter the probability of the event. (b) subtract. 1 - p(not x) = (c) select the answer that makes the equation true. 1 - p(not x) is the same as

Explanation:

Step1: Understand the problem

We need to find the probability of event \(X\) and \(not\ X\) based on the given table.

Step2: Calculate \(P(X)\)

From the table, \(P(X)=\frac{4}{5}\) (sum of probabilities of outcomes where \(X\) occurs: \(\frac{4}{5}\)).

Step3: Calculate \(P(not\ X)\)

We know that \(P(not\ X)=1 - P(X)\). Substituting \(P(X)=\frac{4}{5}\), we get \(P(not\ X)=1-\frac{4}{5}=\frac{1}{5}\).

Step4: Check the relationship \(1 - P(not\ X)\)

\(1 - P(not\ X)=1-\frac{1}{5}=\frac{4}{5}\), and \(P(X)=\frac{4}{5}\).

Answer:

(a) For event \(1\): check the box for \(not\ X\). For events \(2\), \(3\), \(4\), \(5\): check the box for \(X\). \(P(X)=\frac{4}{5}\), \(P(not\ X)=\frac{1}{5}\).
(b) \(1 - P(not\ X)=\frac{4}{5}\) and \(P(X)=\frac{4}{5}\), so \(1 - P(not\ X)=P(X)\).
(c) \(1 - P(not\ X)\) is the same as \(P(X)\).