Question

a drawer contains 4 $20 bills, 3 $10 bills, 7 $5 bills, and 12 one - dollar bills. if one bill is selected at random, what is the probability that it is a $20 bill? round to 4 decimal places.

Explanation:

Step1: Calculate total number of bills

Total bills = \(4 + 3+7 + 12\)

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Step2: Use probability formula

Probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Number of favorable outcomes (number of \(\$20\) bills) \(n = 4\), total number of outcomes \(N=26\). So \(P=\frac{4}{26}\)

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Answer:

\(0.1538\)