QUESTION IMAGE
Question
dihybrid crosses- crosses in which inheritance of two characters are studied
in humans, free ear lobes e are dominant to attached ear lobes e, and the allele for hypercholesterolemia h is dominant to the normal condition h.
hypercholesterolemia results in severely elevated blood cholesterol levels and high risk of heart attack. what gametes can be produced by the following
parents eehh x eehh and what are the expected phenotypic and genotypic ratios for the offspring produced. explain your answer using punnett square.
Step1: Determine gametes
For \(EeHH\):
- For the \(E/e\) gene: \(E\) and \(e\)
- For the \(H/h\) gene: \(H\) (since it is \(HH\))
- Gametes: \(EH\) and \(eH\)
For \(eeHh\):
- For the \(E/e\) gene: \(e\) (since it is \(ee\))
- For the \(H/h\) gene: \(H\) and \(h\)
- Gametes: \(eH\) and \(eh\)
Step2: Create Punnett square
| \(EH\) | \(eH\) | |
|---|---|---|
| \(eh\) | \(EeHh\) | \(eeHh\) |
Step3: Determine genotypes
- \(EeHH\): \(1/4\)
- \(eeHH\): \(1/4\)
- \(EeHh\): \(1/4\)
- \(eeHh\): \(1/4\)
Step4: Determine phenotypes
- Free earlobes, hypercholesterolemia (\(EeHH\) and \(EeHh\)): \(2/4 = 1/2\)
- Attached earlobes, hypercholesterolemia (\(eeHH\) and \(eeHh\)): \(2/4 = 1/2\)
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- Gametes: \(EeHH\) produces \(EH\) and \(eH\); \(eeHh\) produces \(eH\) and \(eh\)
- Genotypic ratio: \(EeHH : eeHH : EeHh : eeHh = 1:1:1:1\)
- Phenotypic ratio: Free earlobes, hypercholesterolemia : Attached earlobes, hypercholesterolemia = \(1:1\)