Question

in a dihybrid cross, if the probability of one event is 3/4 and the other is 1/2, what is their combined probability? 2/4 3/8 1/2 1/8

Explanation:

Step1: Apply the multiplication rule for independent events

For independent events \(A\) and \(B\), the combined probability \(P(A\cap B)=P(A)\times P(B)\)
Here \(P(A)=\frac{3}{4}\) and \(P(B)=\frac{1}{2}\)
So \(P(A\cap B)=\frac{3}{4}\times\frac{1}{2}\)

Step2: Calculate the product

\(\frac{3}{4}\times\frac{1}{2}=\frac{3\times1}{4\times2}=\frac{3}{8}\)

Answer:

\(\frac{3}{8}\)