Question

a die is rolled twice. what is the probability of showing a 1 on the first roll and an even number on the second roll? your answer is :

Explanation:

Step1: Probability of first roll (1)

A die has 6 faces. Probability of rolling a 1: $\frac{1}{6}$.

Step2: Probability of second roll (even)

Even numbers on a die: 2,4,6 (3 outcomes). Probability: $\frac{3}{6}=\frac{1}{2}$.

Step3: Multiply probabilities (independent events)

Since rolls are independent, multiply the two probabilities: $\frac{1}{6} \times \frac{1}{2} = \frac{1}{12}$.

Answer:

$\frac{1}{12}$