Question

1. continued...

a. examples include cellulose and glycogen
b. contains the elements: c, h, o, n, p
c. made of nucleotides
d. includes monosaccharides (glucose)
e. cells can utilize as an immediate source of energy to synthesize atp

1. answer the questions below based off of the figure provided.

chemical structure diagram showing a reaction with two hexose rings on the left, h₂o, and two hexose rings on the right
a. which side of the figure, left or right, is an example of a polymer?
b. on the right side, two molecules of glucose are formed. explain the importance of glucose to the survival of all living things.

1. explain what is happening in the diagram below. use the catalase liver lab as your example. be sure to use the words: substrates, reactants, enzymes, and products.

diagram showing enzyme-substrate interaction: substrate, active site, enzyme, enzyme-substrate complex, products a and b

1. what would happen if the enzyme in #3 above was exposed to a different ph or temperature, other than its optimum environment?

Explanation:

Question 2a

Step1: Recall polymer definition

A polymer is a large molecule made of repeating monomer units.

Step2: Analyze left/right structures

The left side shows a molecule with two hexose (glucose - like) units linked (a disaccharide or part of a polysaccharide), so it's a polymer (made of multiple monomers). The right side has two separate glucose molecules (monomers).

Glucose is a monosaccharide and the primary energy source for cells. During cellular respiration, glucose is broken down (via glycolysis, Krebs cycle, etc.) to synthesize ATP, which provides energy for essential life processes like metabolism, growth, and movement. All living things (from bacteria to plants to animals) rely on glucose (or its derivatives) for energy production to survive.

Step1: Identify components (Catalase Liver Lab)

In the Catalase Liver Lab, the enzyme is catalase, substrate (reactant) is hydrogen peroxide ($\ce{H_2O_2}$).

Step2: Describe the diagram process

1. Substrate (e.g., $\ce{H_2O_2}$) approaches the enzyme (catalase)’s active site.
2. Substrate binds to the active site, forming an enzyme - substrate complex.
3. The enzyme catalyzes the reaction: $\ce{2H_2O_2 \xrightarrow{\text{catalase}} 2H_2O + O_2}$. Products (water and oxygen, labeled A/B in the diagram) are released, and the enzyme is reused.

In the diagram: Substrates (reactants) bind to enzyme’s active site, form enzyme - substrate complex, then react to form products (A and B), with the enzyme remaining to catalyze more reactions.

Answer:

Left side

Question 2b