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QUESTION IMAGE

complete the table so that it contains values that satisfy the equation…

Question

complete the table so that it contains values that satisfy the equation y = -2x + 5. then, use the numbers to match to each form. not all numbers will be used.

Explanation:

Step1: Identify the equation

The given equation is \( y = -2x + 5 \). We need to find \( x \) values (from the left set) and compute \( y \), or find \( y \) values and solve for \( x \), then match to the right boxes.

Step2: Test each \( x \) (or \( y \)) value

Let's list the left values (assuming they are \( x \) or \( y \)). Let's check possible \( x \) values:

  • If \( x = 0 \): \( y = -2(0)+5 = 5 \)
  • If \( x = 1 \): \( y = -2(1)+5 = 3 \)
  • If \( x = 2 \): \( y = -2(2)+5 = 1 \)
  • If \( x = 3 \): \( y = -2(3)+5 = -1 \)
  • If \( x = -1 \): \( y = -2(-1)+5 = 7 \) (but 7 might not be in right? Wait, maybe \( y \) is given. Let's reverse: solve for \( x \) when \( y \) is known.

Suppose right boxes have \( y \) values: Let's take \( y = 5 \), solve \( 5 = -2x +5 \Rightarrow x=0 \). \( y=3 \Rightarrow 3=-2x+5 \Rightarrow 2x=2 \Rightarrow x=1 \). \( y=1 \Rightarrow 1=-2x+5 \Rightarrow 2x=4 \Rightarrow x=2 \). \( y=-1 \Rightarrow -1=-2x+5 \Rightarrow 2x=6 \Rightarrow x=3 \). \( y=7 \Rightarrow 7=-2x+5 \Rightarrow 2x=-2 \Rightarrow x=-1 \).

Now match \( x \) (left) to \( y \) (right) using \( y=-2x+5 \).

For example, if left has \( x=0 \), \( y=5 \); \( x=1 \), \( y=3 \); \( x=2 \), \( y=1 \); \( x=3 \), \( y=-1 \); \( x=-1 \), \( y=7 \).

So we pair each \( x \) with its \( y \) via the equation.

Answer:

To solve, use \( y = -2x + 5 \):

  • For \( x = 0 \), \( y = 5 \); \( x = 1 \), \( y = 3 \); \( x = 2 \), \( y = 1 \); \( x = 3 \), \( y = -1 \); \( x = -1 \), \( y = 7 \).

Match each \( x \) (left) to its \( y \) (right) using this calculation.

(Note: Since the image's exact values are a bit unclear, the process is to substitute \( x \) into \( y = -2x + 5 \) to find corresponding \( y \), or vice versa, and pair the boxes.)