QUESTION IMAGE
Question
complete the following table. round each of your answers to 3 significant digits.
| energy content when eaten | |||
| food | cal | kcal | kj |
| a slice of cooked bacon | $3.60 \times 10^4$ | $\square$ | $\square$ |
| a small apple | $\square$ | 125. | $\square$ |
| a 12-ounce soft drink | $\square$ | $\square$ | 628. |
To solve this problem, we need to convert between different units of energy: calories (cal), kilocalories (kcal), and kilojoules (kJ). The key conversion factors are:
- \( 1 \, \text{kcal} = 1000 \, \text{cal} \)
- \( 1 \, \text{kcal} = 4.184 \, \text{kJ} \)
Step 1: Slice of Cooked Bacon
We know the energy in calories is \( 3.60 \times 10^4 \, \text{cal} \).
Convert cal to kcal:
Since \( 1 \, \text{kcal} = 1000 \, \text{cal} \), divide by 1000:
Convert kcal to kJ:
Using \( 1 \, \text{kcal} = 4.184 \, \text{kJ} \):
Step 2: Small Apple
We know the energy in kcal is \( 125 \, \text{kcal} \).
Convert kcal to cal:
Multiply by 1000:
Convert kcal to kJ:
Using \( 1 \, \text{kcal} = 4.184 \, \text{kJ} \):
Step 3: 12-Ounce Soft Drink
We know the energy in kJ is \( 628 \, \text{kJ} \).
Convert kJ to kcal:
Divide by 4.184:
Convert kcal to cal:
Multiply by 1000:
Final Table (Filled)
| Food | cal | kcal | kJ |
|---|---|---|---|
| Small Apple | \( 1.25 \times 10^5 \) | 125 | 523 |
| 12-Ounce Soft Drink | \( 1.50 \times 10^5 \) | 150 | 628 |
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s (Filled in Boxes):
- Slice of Cooked Bacon (kcal): \( \boldsymbol{36.0} \)
- Slice of Cooked Bacon (kJ): \( \boldsymbol{151} \)
- Small Apple (cal): \( \boldsymbol{1.25 \times 10^5} \)
- Small Apple (kJ): \( \boldsymbol{523} \)
- 12-Ounce Soft Drink (cal): \( \boldsymbol{1.50 \times 10^5} \)
- 12-Ounce Soft Drink (kcal): \( \boldsymbol{150} \)