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Question
colleen decided to ride her bike from her home to visit her friend dave. two miles away from home, her bike got a flat tire and she had to walk the remaining four miles to daves home. she could not repair the tire and had to walk all the way back home. how many more miles did colleen walk than she rode?
colleen walked □ more miles than she rode.
Step1: Find miles ridden
Colleen rode her bike 2 miles (before the flat tire).
Step2: Find miles walked
She walked 4 miles to Dave's home and then 6 miles back home (2 + 4 = 6 miles total distance to Dave's, so walking back is 6 miles? Wait, no. Wait, original trip: rode 2, walked 4 to Dave's. Then walked back: total distance from home to Dave's is 2 + 4 = 6 miles. So walking back is 6 miles. Wait, no, the problem says "walk the remaining four miles to Dave’s home" – so home to Dave's is 2 (ridden) + 4 (walked) = 6 miles. Then she walked back home, so that's 6 miles walked back. Wait, no, maybe I misread. Wait, the problem: "Two miles away from home, her bike got a flat tire and she had to walk the remaining four miles to Dave’s home. She could not repair the tire and had to walk all the way back home." So miles ridden: 2. Miles walked: 4 (to Dave's) + 6 (back home? Wait, no: home to Dave's is 2 + 4 = 6 miles. So walking back is 6 miles? Wait, no, the "remaining four miles" – so from home, rode 2, then walked 4 to Dave's. So distance from home to Dave's is 2 + 4 = 6 miles. Then she walked back home: that's 6 miles. So total walked: 4 + 6 = 10. Total ridden: 2. Then the difference is 10 - 2 = 8? Wait, no, maybe I made a mistake. Wait, let's re-express:
Ridden: 2 miles (from home to 2 miles away, where bike flat).
Walked to Dave's: 4 miles (from 2 miles away to Dave's, so total home to Dave's is 2 + 4 = 6 miles).
Then walked back home: 6 miles (since Dave's is 6 miles from home).
Wait, but the problem says "how many more miles did Colleen walk than she rode?"
So ridden: 2 miles.
Walked: 4 (to Dave's) + 6 (back home) = 10 miles.
Difference: 10 - 2 = 8? Wait, no, maybe the return trip is not 6 miles. Wait, no, the distance from home to Dave's is 2 (ridden) + 4 (walked) = 6 miles. So walking back is 6 miles. So total walked: 4 + 6 = 10. Ridden: 2. 10 - 2 = 8. Wait, but maybe I misread. Wait, the problem: "Two miles away from home, her bike got a flat tire and she had to walk the remaining four miles to Dave’s home." So home to Dave's is 2 + 4 = 6 miles. Then she walked back home: so that's 6 miles. So walked: 4 (to Dave's) + 6 (back) = 10. Ridden: 2. 10 - 2 = 8. Wait, but maybe the return trip is not 6 miles. Wait, no, the distance from home to Dave's is 6 miles, so walking back is 6 miles. So total walked: 4 + 6 = 10. Ridden: 2. Difference: 10 - 2 = 8. Wait, but let's check again.
Wait, maybe the return trip is 6 miles? Wait, home to Dave's: 2 (ridden) + 4 (walked) = 6. So walking back is 6. So walked: 4 + 6 = 10. Ridden: 2. 10 - 2 = 8. So the answer is 8.
Wait, but maybe I made a mistake. Let's do it step by step:
- Miles ridden: 2 (from home to 2 miles out).
- Miles walked to Dave's: 4 (from 2 miles out to Dave's).
- Miles walked back home: total distance from home to Dave's is 2 + 4 = 6 miles, so walking back is 6 miles.
- Total walked: 4 + 6 = 10 miles.
- Total ridden: 2 miles.
- Difference: 10 - 2 = 8 miles.
Yes, that makes sense. So Colleen walked 8 more miles than she rode.
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