Question

clyde has a homozygous dominant genotype for his hand (hh), and amelia has the recessive trait of no
phenotype probability (%)
hand: 100%
no hand: 0%

Explanation:

Step1: Determine Amelia's genotype

Since Amelia has the recessive trait (no hand), her genotype must be homozygous recessive, so \( hh \).

Step2: Set up the Punnett square

Clyde is \( HH \), so he can only produce \( H \) gametes. Amelia is \( hh \), so she can only produce \( h \) gametes.
The Punnett square will have all offspring with genotype \( Hh \).

Step3: Determine phenotype probabilities

The dominant trait (hand) is expressed in \( Hh \) (since \( H \) is dominant). So all offspring (100%) will have the hand phenotype, and 0% will have no hand.

Answer:

The Punnett square for Clyde (\( HH \)) and Amelia (\( hh \)) will have all cells as \( Hh \). The phenotype probabilities are Hand: 100%, No hand: 0% (consistent with the given values, as all offspring are \( Hh \) and show the dominant hand trait).